KoolAjax supports loading any resource files at client-side. You just need to use the load() function and provide your path of resource file as parameter.
KoolAjax also provides a cross-browsers XML parsing function. This will help transform text XML into object XML.
Above example show how we can load an XML file and parse it to get data.
span style="color: #ff0000;">"/KoolAjax/koolajax.php";
$koolajax->scriptFolder = $KoolControlsFolder."/KoolAjax""text/css"#f4f4f4;}
div.color1 { height:10px;}
#wrapper{ width : 500px;height:170px;}
"indent indent_right topspacing bottomspacing" id = "wrapper" >
<div id="info"" " >
<input type="button" id="btn1" onclick="loadXMLnow();" value="Load XML data" />
<input type="button" id="btn2" onclick="reload();" value="Unload" disabled />
</div>
<div id="dataXml" >
Data will appear benath here :
</div>
</div>
<script type="text/javascript""Employees.xml"'dataXml').innerHTML = """employee""<H3>Here is the result</H3><b><u><div class='cl1 '>Name</div><div class='cl2'>IDEm</div><div class='cl3'>Gender</div><div class='cl4'>Age</div><div class='cl5'>Dept.</div></u></b>""<div class='cl1'>""</div>";
s += "<div class='cl2'>" + x[i].attributes.getNamedItem("id""</div>";
s += "<div class='cl3'> " + x[i].attributes.getNamedItem("gender""</div>";
s += "<div class='cl4'> " + x[i].attributes.getNamedItem("age""</div>";
s += "<div class='cl5'> " + x[i].attributes.getNamedItem("dept""</div></div>"'dataXml''btn2''btn1'"clear:both"></div>
span style="color: #ff0000;">"1.0" encoding="utf-8""0V1""Male" age="19" dept="Technical support""J02""Male" age="24" dept="Maketing""C05""Female" age="21" dept="Sales">Ranjit Kapoor</employee>
<employee id="BB4""Female" age="31" dept="IT management">Anna Kapoor</employee>
<employee id="005""Male" age="21" dept="Sales">Ran Jinemor</employee>
</company>
KoolAjax - Great PHP Ajax FrameworkFullVersion 3.0.0.0 released on 10/22/2012